\(\left(2x-3\right).\left(\frac{3}{4}x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x-3=0\\\frac{3}{4}x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=3\\\frac{3}{4}x=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{3}{2}\\x=-\frac{4}{3}\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{3}{2};-\frac{4}{3}\right\}.\)
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