x(x-1)=x-1
=>x2-x=x-1
=>x2-x+x=1
=>x2= 1
=>x=1 ;x=-1
|x(x-1)|=x-1
\(\Leftrightarrow\left\{{}\begin{matrix}x>=1\\\left[x\left(x-1\right)\right]^2=\left(x-1\right)^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>=1\\\left(x^2-x-x+1\right)\left(x^2-x+x-1\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=1\\\left(x^2-2x+1\right)\left(x^2-1\right)=0\end{matrix}\right.\Leftrightarrow x=1\)