Question

Tìm x biết:

          x=\(\frac{a}{b+c}\)=\(\frac{b}{c+a}\)=\(\frac{c}{a+b}\)

Answer 1

\(\frac{a}{b+c}=\frac{b}{c+a}=\frac{c}{a+b}\)

áp dụng dãy tỉ số bằng nhau

=> x=\(\frac{a+b+c}{b+c+a+c+a+b}=\frac{\left(a+b+c\right)}{2\left(a+b+c\right)}=\frac{1}{2}\)

vậy x=1/2

Answer 2

\(\frac{a}{b+c}=\frac{b}{c+a}=\frac{c}{a+b}=\frac{a+b+c}{2\left(a+b+c\right)}=\frac{1}{2}\)

=> x = 1/2