\(\left|x-2010\right|+\left|x-2012\right|=2\)
\(\Rightarrow\left|2010-x\right|+\left|x-2012\right|=2\)
Ta có : \(\left|2010-x\right|+\left|x-2012\right|\ge\left|2010-x+x-2012\right|=2\)
Dấu "=" xảy ra \(\Leftrightarrow\left(2010-x\right)\left(x-2012\right)\ge0\)
\(\Leftrightarrow2010\le x\le2012\)
Vậy \(\Leftrightarrow2010\le x\le2012\)
Giải phương trình sau:
\(\frac{\left(2009-x\right)^2+\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}{\left(2009-x\right)^2-\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}=\frac{19}{49}\)
Tìm x biết : \(\left(5-2x\right)\left(2x+7\right)-4x^2-25=0\)
Tìm x biết
a. x ( x - 2 ) - x +2 = 0
b. \(x^2\left(x^2+1\right)-x^2-1=0\)
c. \(5x\left(x-3\right)^2-5\left(x-1\right)^3+15\left(x+2\right)\left(x-2\right)=5\)
Tìm x, biết :
a) \(x^3-\dfrac{1}{4}x=0\)
b) \(\left(2x-1\right)^2-\left(x+3\right)^2=0\)
c) \(x^2\left(x-3\right)+12-4x=0\)
tìm x,biết :
a) \(x\left(x+5\right)\left(x-5\right)=\left(x+2\right)\left(x^2-2x+4\right)=3\)
b) \(2x^3+2\sqrt{2}x^2+x=0\)
Phân tích các đa thức sau thành nhân tử ( đặt biến phụ )
a. \(\left(x^2+x\right)^2-14\left(x^2+x\right)+24\)
b. \(\left(x^2+x\right)^2+4x^2+4x-12\)
c. \(x^4+2x^3+5x^2+4x-12\)
d.\(\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)+1\)
e. \(\left(x+1\right)\left(x+3\right)\left(x+5\right)\left(x+7\right)+15\)
f. \(\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)-24\)
Tìm x, biết:
1) \(x^2-6x=0\)
2) \(2x^3-5x^2-12x=0\)
3) \(\left(x+1\right)\left(x+2\right)-\left(x+2\right)\left(x+3\right)=0\)
Bài 3
a) \(\left(x^2+x\right)^2+4x^2+4x\)
b) \(x\left(x+1\right)\left(x+2\right)\left(x+3\right)+1\)
c) \(\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)-24\)
tìm x biết
1, 4x^2+4xy+4y^2-6y+3=0
2, \(\left(x+2\right)^2-x^4+4=0\)
3,\(4y^2+4xy+4y^2-6y+3=0\)
2,phân tích cac da tthuc thanh nhân tử
1,1,\(\left(x+3\right)\left(x+5\right)\left(x+7\right)\left(x+9\right)-125\)
2,\(\left(x^2+x\right)^2-2\left(x^2+x\right)-15\)
