a) \(\left(x+1\right)^3+\left(x-2\right)^3-2x^2\left(x-1,5\right)=5\)
\(\Leftrightarrow\left(x^3+3x^2+3x+1\right)+\left(x^3-6x^2+12x-8\right)-\left(2x^3-3x^2\right)=5\)
\(\Leftrightarrow x^3+3x^2+3x+1+x^3-6x^2+12x-8-2x^3+3x^2=5\)
\(\Leftrightarrow15x-12=0\)
\(\Leftrightarrow15x=12\)
\(\Leftrightarrow x=\dfrac{4}{5}\)
Vậy \(S=\left\{\dfrac{4}{5}\right\}\)
(bạn ơi xem lại đề câu b ik để mik giải lun)