Question

Tìm x:

a, \(\left(x+2\right)^2=\dfrac{1}{2}-\dfrac{1}{3}\)

b, \(\left(x-1\right)^{x+2}=\left(x-1\right)^2\)

c, \(\left(1-3x\right)^3=-64\)

Answer 1

b) (x-1)^x+2 =(x-1)²

=> x+2=2

=> x=0

vậy

c) (1-3x)³=-64

=> 1-3x=-4

=> -3x=-4-1

=> -3x=-5

=> x=5/3

vậy ....

Answer 2

Làm nốt ::v

\(a.\left(x+2\right)^2=\dfrac{1}{2}-\dfrac{1}{3}\)

\(\Leftrightarrow\left(x+2\right)^2=\dfrac{1}{6}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+2=\sqrt{\dfrac{1}{6}}\\x+2=-\sqrt{\dfrac{1}{6}}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\sqrt{\dfrac{1}{6}}-2\\x=-\sqrt{\dfrac{1}{6}}-2\end{matrix}\right.\)

KL...........