Question

Tìm x

a) \(\dfrac{-2}{3}\) x (\(\dfrac{1}{3}\)- \(\dfrac{1}{2}\)-\(\dfrac{3}{4}\)) \(\ge\) x \(\ge\) -4\(\dfrac{1}{3}\) x (\(\dfrac{1}{2}\) - \(\dfrac{1}{6}\))

b) 21% +\(\dfrac{3}{4}\) -\(\dfrac{11}{5}\) \(\ge\) 2x -1 \(\ge\) -3\(\dfrac{1}{2}\) + 3\(\dfrac{1}{5}\)

c) 43\(\dfrac{1}{2}\) - 39\(\dfrac{1}{5}\) \(\le\) -3x +4 \(\le\) 9\(\dfrac{1}{5}\) + 50 \(\dfrac{1}{7}\)

GIÚP MK NHA ĐANG CẦN GẤP HẠN CHÓT CHIỀU MAI NỘP

Answer 1

a: \(\Leftrightarrow-\dfrac{2}{3}\cdot\dfrac{4-6-9}{12}\ge x\ge-\dfrac{13}{3}\cdot\dfrac{3-1}{6}\)

\(\Leftrightarrow-\dfrac{2}{3}\cdot\dfrac{-11}{12}\ge x\ge\dfrac{-13}{3}\cdot\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{22}{36}\ge x\ge\dfrac{-13}{9}\)

mà x là số nguyên

nên \(x\in\left\{0;-1\right\}\)

b: \(\Leftrightarrow\dfrac{21}{100}+\dfrac{75}{100}-\dfrac{220}{100}>=2x-1>=-3-\dfrac{1}{2}+3+\dfrac{1}{5}\)

\(\Leftrightarrow\dfrac{-124}{100}\ge2x-1\ge\dfrac{-3}{10}\)

\(\Leftrightarrow-\dfrac{124}{100}+1\ge2x>=\dfrac{-3}{10}+1\)

\(\Leftrightarrow\dfrac{-3}{25}\ge2x\ge\dfrac{7}{10}\)(vô lý)

=>x không có giá trị

c: \(\Leftrightarrow43+\dfrac{1}{2}-39-\dfrac{1}{5}\le-3x+4\le9+\dfrac{1}{5}+50+\dfrac{1}{7}\)

\(\Leftrightarrow3+\dfrac{3}{10}\le-3x+4\le59+\dfrac{12}{35}\)

\(\Leftrightarrow\dfrac{33}{10}-4\le-3x\le59+\dfrac{12}{35}-4\)

\(\Leftrightarrow\dfrac{-7}{10}\le-3x\le\dfrac{1937}{35}\)

\(\Leftrightarrow\dfrac{7}{30}\ge x\ge-\dfrac{1937}{105}\)

mà x là số nguyên

nên \(x\in\left\{0;-1;-2;...;-18\right\}\)