Question

Tìm x

A) (2x -1)^2 - (2x + 3)(2x-1)=0

B) (x+5)(x-2) - (x-3)(x+3)=0

Answer 1

a)

\(\left(2x-1\right)^2-\left(2x+3\right)\left(2x-1\right)=0\\ \Rightarrow\left(2x-1\right)\left(\left(2x-1\right)-\left(2x+3\right)\right)=0\\ \Rightarrow\left(2x-1\right)\left(-4\right)=0\\ \Rightarrow2x-1=0\\ \Rightarrow x=\dfrac{1}{2}\)

b)

\(\left(x+5\right)\left(x-2\right)-\left(x-3\right)\left(x+3\right)=0\\ \Rightarrow x^2+3x-10-\left(x^2-9\right)=0\\ \Rightarrow3x-1=0\\ \Rightarrow x=\dfrac{1}{3}\)