Question

TÌM x

2xy - x^2 - y^2 + 16

Answer 1

\(2xy-x^2-y^2+16=0\) à bn

Answer 2

\(2xy-x^2-y^2+16\)

\(=( 2xy-x^2-y^2 )+16 \)

\(=16-(x-y)^2\)

\(=(4+x-y).(4-x+y)\)

Answer 3

\(2xy-x^2-y^2+16=-\left(x^2-2xy+y^2\right)+16=-\left(x-y\right)^2+4^2=\left[\left(x-y\right)^2-4^2\right]=\left(x-y-4\right)\left(x-y+4\right)\)

Answer 4

\(2xy-x^2-y^2+16\)

\(=-\left(x^2-2xy+y^2-16\right)\)

\(=-\left[\left(x-y\right)^2-4^2\right]\)

\(=-\left(x-y-4\right)\left(x-y+4\right)\)