2x(6x-3)+6x(5-2x)=48
=> 12x2-6x+6x(5-2x)=48
=>6x(2x-1)+6x(5-2x)=48
=>6x(2x-1+5-2x)=48
=>6x+4=48
=>6x=42
=>x=7
À nhầm mình tính sai đấy
6x(2x-1+5-2x)=48
=>6x.4=48
=>24x=48
=>x=2
rút gọn biểu thức:
a) (6x + 1)2 (6x - 1)2 - 2 (1 + 6x). (6x - 1)
b) (2x - 3) . (2x + 3) - (x + 5)2 - (x - 1) . (x + 2)
Tìm x , biết :
a) (3x -1)(2x+7) -(x+1)(6x-5) =16
b) (2x +3)2-2(2x+3)(2x-5)+(2x-5)2= x2+6x+64
c) (x4+2x3+10x-25): (x2+5)=3
2)x^2-2xy+y^2-2x+2y
3)3x^2-2x-5
4)16-x^2+4xy-4x^2
5)x^2-2x+1-y^2
6)x^2+8x+15
7)(x^2+6x+8)(x^2+14x+48)-9
8)(x^2-8x+15)(x^2-16x+60)-24x^2
9)x^5+x^4+1
10)x^4-x^3-10x^2+2x+4
Tìm x, biết
a) 3x3 - 6x2 = 0
b) x ( x-4) - 12x + 48 =0
c) x (x-4)- (x2-8) =0
d) 2x (x-5 ) - x (2x+3) =16
e) (4x2-1) - (x-1)2 = -3
Tìm x
(2x-3)(x+1)+(4x3-6x2-6x):(-2x)=18
Tìm x
(2x-3)(x+1)+(4x3-6x2-6x):(-2x)=18
Tìm x
(2x-3)(x+1)+(4x3-6x2-6x):(-2x)=18
2x(3x-7)(6x+5)(x-3)-2019=0
Tìm x nha
phân tích
1,(x-2)^4+(x-3)^4-1
2,(x-1)^4+(x+3)^4-512
3,(x-2)^6+(x-4)^6-64
4,x^4-3x^3+6x^2+3x+1
5,3x^4-2x^3-15x^2-2x+3
6,x^6-2x^5-4x^4+6x^3+4x^2-2x-1
