\(2\left(x-\dfrac{1}{2}\right)-5\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{3}\)
\(\Leftrightarrow2\left(x-\dfrac{1}{2}\right)-5\left(x+\dfrac{3}{5}\right)=-\left(x-\dfrac{1}{3}\right)\)
\(\Leftrightarrow2\left(x-\dfrac{1}{2}\right)-5\left(x+\dfrac{3}{5}\right)+\left(x-\dfrac{1}{3}\right)=0\)
\(\Leftrightarrow2x-1-5x-3+x-\dfrac{1}{3}=0\)
\(\Leftrightarrow-2x-\dfrac{13}{3}=0\)
\(\Leftrightarrow-2x=\dfrac{13}{3}\)
\(\Leftrightarrow x=\dfrac{13}{3}:-2\)
\(\Leftrightarrow x=\dfrac{-13}{6}\)
Vậy \(x=\dfrac{-13}{6}\)