Ta thấy: \(10z⋮3\Rightarrow z=3k\left(k\in Z\right)\)
\(\Rightarrow6x+15y+30k=3\)
\(\Leftrightarrow2x+5y+10k=1\)
\(\Leftrightarrow2x+5y=1-10k\)
\(\Rightarrow x=\dfrac{1-10k-5y}{2}=-5k-2y+\dfrac{1-y}{2}\)
Đặt \(t=\dfrac{1-y}{2}\left(t\in Z\right)\)
Ta có: y=1-2t;
x=5t-5k-2;
z=3k.
Pt có nghiệm là (1-2t;5t-5k-2;3k)