a) \(\left(\dfrac{1}{2}\right)^{2n-1}=\dfrac{1}{8}\)
\(\Rightarrow\left(\dfrac{1}{2}\right)^{2n-1}=\left(\dfrac{1}{2}\right)^3\)
\(\Rightarrow2n-1=3\)
\(\Rightarrow2n=4\)
\(\Rightarrow n=2\)
a) \(\left(\dfrac{1}{2}\right)^{2n-1}=\dfrac{1}{8}\)
\(\Rightarrow2^{-\left(2n-1\right)}=2^{-3}\)
\(\Rightarrow2^{-2n+1}=2^{-3}\)
\(\Rightarrow-2n+1=-3\)
\(\Rightarrow-2n=-4\)
\(\Rightarrow n=-2\)
Vậy ...
b) \(\left(\dfrac{7}{5}\right)^n=\dfrac{343}{125}\)
\(\Rightarrow\left(\dfrac{7}{5}\right)^n=\left(\dfrac{7}{5}\right)^3\)
\(\Rightarrow n=3\)
Vậy ....
a. )\(\left(\dfrac{1}{2}\right)^{2n-1}\)=\(\dfrac{1}{8}\)
=> 2n-1=3
=>2n=3+1
=>2n=4
=>n=4:2=2
b. \(\left(\dfrac{7}{5}\right)\)^n = \(\left(\dfrac{343}{125}\right)\)
=> n= 3
a. \(\left(\dfrac{1}{2}\right)^{2n-1}=\dfrac{1}{8}\)
\(\Rightarrow\left(\dfrac{1}{2}\right)^{2n-1}=\left(\dfrac{1}{2}\right)^3\)
\(\Rightarrow2n-1=3\)
\(\Rightarrow2n=3+1=4\)
\(\Rightarrow n=4:2=2\)
Vậy....
b. \(\left(\dfrac{7}{5}\right)^n=\dfrac{344}{125}\)
\(\Rightarrow\left(\dfrac{7}{5}\right)^n=\left(\dfrac{7}{3}\right)^3\)
\(\Rightarrow n=3\)
Vậy..........
Lưu Hạ Vi sai kết quả câu a) mà vẫn được tick ;
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