a. \(\left(\dfrac{1}{2}+1,5\right)x=\dfrac{1}{5}\Rightarrow2x=\dfrac{1}{5}\Rightarrow x=\dfrac{1}{5}:2=0,1\)
Vậy \(x=0,1\)
b. \(\left(-1\dfrac{3}{5}+x\right):\dfrac{12}{13}=2\dfrac{1}{6}\Rightarrow-1\dfrac{3}{5}+x=\dfrac{13}{6}\cdot\dfrac{12}{13}=2\Rightarrow x=2+1\dfrac{3}{5}=3,6\)
Vậy \(x=3,6\)
c. \(-\dfrac{4}{7}x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1\dfrac{2}{3}\right)\Rightarrow-\dfrac{4}{7}x+\dfrac{7}{5}=-\dfrac{3}{40}\Rightarrow-\dfrac{4}{7}x=-\dfrac{3}{40}-\dfrac{7}{5}=-\dfrac{59}{40}\Rightarrow x=\left(-\dfrac{59}{40}\right):\left(-\dfrac{4}{7}\right)=2,58125\)
Vậy \(x=2,58125\)