a) 3 \(⋮\) n+5
\(\Rightarrow n+5\inƯ\left(3\right)=\left\{1;3;-1;-3\right\}\)
\(\Rightarrow n\in\left\{-4;-2;-6;-8\right\}\)
Vậy.....................................
a: =>\(n+5\in\left\{1;-1;3;-3\right\}\)
=>\(n\in\left\{-4;-6;-2;-8\right\}\)
b: =>-6n+4 chia hết cho 2n+1
=>-6n-3+7 chia hết cho 2n+1
=>\(2n+1\in\left\{1;-1;7;-7\right\}\)
=>\(n\in\left\{0;-1;3;-4\right\}\)