\(2x^2-3x-3=-7m\)
Xét hàm \(f\left(x\right)=2x^2-3x-3\) trên \(\left[-1;2\right]\)
\(f\left(-1\right)=2\) ; \(f\left(2\right)=-1\); \(f\left(-\frac{b}{2a}\right)=f\left(\frac{3}{4}\right)=-\frac{33}{8}\)
\(\Rightarrow-\frac{33}{8}\le f\left(x\right)\le2\)
\(\Rightarrow\) Để pt đã cho có nghiệm thì \(-\frac{33}{8}\le-7m\le2\)
\(\Rightarrow-\frac{2}{7}\le m\le\frac{33}{56}\)