\(3x-\left|2x-1\right|-2=0\)
\(\Leftrightarrow3x-\left|2x-1\right|=2\)
\(\Leftrightarrow\left|2x-1\right|=3x-2\)
Xét trường hợp 1: \(2x-1=3x-2\)
\(\Rightarrow2x-1-\left(3x-2\right)=0\)
\(\Rightarrow2x-1-3x+2=0\)
\(\Rightarrow-x+1=0\)
\(\Rightarrow-x=-1\)
\(\Rightarrow x=1\)
Xét trường hợp 1: \(2x-1=-\left(3x-2\right)\)
\(\Rightarrow2x-1-\left[-\left(3x-2\right)\right]=0\)
\(\Rightarrow2x-1+3x-2=0\)
\(\Rightarrow5x-3=0\)
\(\Rightarrow5x=3\)
\(\Rightarrow x=\dfrac{3}{5}\)
Vậy \(x=1\) hoặc \(x=\dfrac{3}{5}\)
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