\(\sqrt{\dfrac{3}{4}}+\sqrt{\dfrac{1}{3}}+\sqrt{\dfrac{1}{12}}\)
=\(\dfrac{3}{2}\sqrt{\dfrac{1}{3}}+\sqrt{\dfrac{1}{3}}+\dfrac{1}{2}\sqrt{\dfrac{1}{3}}\)
=\(\sqrt{\dfrac{1}{3}}\left(\dfrac{3}{2}+1+\dfrac{1}{2}\right)\)
=\(3\sqrt{\dfrac{1}{3}}=\sqrt{3}\)