Chương 3: PHƯƠNG TRÌNH, HỆ PHƯƠNG TRÌNH
Các câu hỏi tương tự
\(\left\{{}\begin{matrix}\sqrt{x+1}+\sqrt{y+1}=\sqrt{4-x+5y}\\x^2+y+2=\sqrt{5\left(2x-y+1\right)}+\sqrt{3x+2}\end{matrix}\right.\)
Ai giúp em bài này vs ạ :< Ở pt trên em làm ra được x = y và x = 4y+3 rồi nhưng thay vào pt dưới vẫn không ra ạ :< Em cảm ơn ạ
giải dùm mình với ạ <3
1. \(\sqrt{x+2}+x^2-x-2\le\sqrt{3x-2}\)
2. \(\sqrt{2x+1}+\sqrt[4]{2x-1}< \sqrt{x-1}+\sqrt{x^2-2x+3}\)
3. \(\sqrt[3]{3-2x}+\frac{5}{\sqrt{2x-1}}-2x\le6\)
4. \(\left(x+3\right)\sqrt{x+1}+\left(x-3\right)\sqrt{1-x}+2x=0\)
giúp mik giải bài hệ pt vs ạ!
1,left{{}begin{matrix}x^2+y^2+dfrac{2xy}{x+y}1sqrt{x+y}x^2-yend{matrix}right.
2,left{{}begin{matrix}2x^3+xy^2+xy^3+4x^2y+2ysqrt{4x^2+x+6}-5sqrt{1+2y}1-4yend{matrix}right.
3,left{{}begin{matrix}2x^2+sqrt{2}xleft(x+yright)y+sqrt{x+y}sqrt{x-1}+xysqrt{y^2+21}end{matrix}right.
4,left{{}begin{matrix}sqrt{9y^2+left(2y+3right)left(y-xright)}+4sqrt{xy}7xleft(2y-1right)sqrt{1+x}+left(2y+1right)sqrt{1-x}2yend{matrix}right.
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giúp mik giải bài hệ pt vs ạ!
1,\(\left\{{}\begin{matrix}x^2+y^2+\dfrac{2xy}{x+y}=1\\\sqrt{x+y}=x^2-y\end{matrix}\right.\)
2,\(\left\{{}\begin{matrix}2x^3+xy^2+x=y^3+4x^2y+2y\\\sqrt{4x^2+x+6}-5\sqrt{1+2y}=1-4y\end{matrix}\right.\)
3,\(\left\{{}\begin{matrix}2x^2+\sqrt{2}x=\left(x+y\right)y+\sqrt{x+y}\\\sqrt{x-1}+xy=\sqrt{y^2+21}\end{matrix}\right.\)
4,\(\left\{{}\begin{matrix}\sqrt{9y^2+\left(2y+3\right)\left(y-x\right)}+4\sqrt{xy}=7x\\\left(2y-1\right)\sqrt{1+x}+\left(2y+1\right)\sqrt{1-x}=2y\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x+1=\sqrt{2+\sqrt{y+3}}\\y+1=\sqrt{2+\sqrt{x+3}}\end{matrix}\right.\)
Em cảm ơn ạ !!!!
7 tháng 11 2019 lúc 16:04
giải pt
a) \(\sqrt{x+2\sqrt{x-1}}+3\sqrt{x+8-6\sqrt{x-1}}=1-x\)
b) \(\sqrt{x\sqrt{x-1}-2x+2}+\sqrt{\left(x+3\right)\sqrt{x-1}-4x+4}=\sqrt{x-1}\)
c) \(\sqrt{14x+14\sqrt{14x-49}}+\sqrt{14x-14\sqrt{14x-49}}=14\)
d) \(\sqrt{2x-2\sqrt{2x-1}}-2\sqrt{2x+3-4\sqrt{2x-1}}+3\sqrt{2x+8-6\sqrt{2x-1}}=4\)
giải giúp mik bt này vs mn!
1)left{{}begin{matrix}2x^2+y^2+x3left(xy+1right)+2ydfrac{2}{3+sqrt{2x-y}}+dfrac{2}{3+sqrt{4-5x}}dfrac{9}{2x-y+9}end{matrix}right.
2)left{{}begin{matrix}left(x+3y+1right)sqrt{2xy+2y}yleft(3x+4y+3right)left(sqrt{x+3}-sqrt{2y-2}right)left(x-3+sqrt{x^2+x+2y-4}right)4end{matrix}right.
3)left{{}begin{matrix}x-dfrac{1}{x}y-dfrac{1}{y}2yx^3+1end{matrix}right.
4)left{{}begin{matrix}sqrt{2x-3}left(y^2+2011right)left(5-yright)+sqrt{y}yleft(y-x+2right)3x+3end{matrix}right.
5...
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giải giúp mik bt này vs mn!
1)\(\left\{{}\begin{matrix}2x^2+y^2+x=3\left(xy+1\right)+2y\\\dfrac{2}{3+\sqrt{2x-y}}+\dfrac{2}{3+\sqrt{4-5x}}=\dfrac{9}{2x-y+9}\end{matrix}\right.\)
2)\(\left\{{}\begin{matrix}\left(x+3y+1\right)\sqrt{2xy+2y}=y\left(3x+4y+3\right)\\\left(\sqrt{x+3}-\sqrt{2y-2}\right)\left(x-3+\sqrt{x^2+x+2y-4}\right)=4\end{matrix}\right.\)
3)\(\left\{{}\begin{matrix}x-\dfrac{1}{x}=y-\dfrac{1}{y}\\2y=x^3+1\end{matrix}\right.\)
4)\(\left\{{}\begin{matrix}\sqrt{2x-3}=\left(y^2+2011\right)\left(5-y\right)+\sqrt{y}\\y\left(y-x+2\right)=3x+3\end{matrix}\right.\)
5)\(\left\{{}\begin{matrix}x^3+2x^2=x^2y+2xy\\2\sqrt{x^2-2y-1}+\sqrt[3]{y^3-14=x-2}\end{matrix}\right.\)
23 tháng 11 2019 lúc 23:32
giải pt
a) \(\sqrt{x+1}+\sqrt{x}+2\sqrt{x^2+x}=1-2x\)
b) \(\sqrt{x-2}-\sqrt{x+2}=2\sqrt{x^2-4}-2x+2\)
c) \(\sqrt{2x+3}+\sqrt{x+1}=3x+2\sqrt{2x^2+5x+3}-16\)
d) \(2\sqrt{x}\left(\sqrt{x+1}-2\sqrt{x}\right)+\sqrt{x+1}+\sqrt{x}=1-6x\)
e) \(x^2+2x+\sqrt{x+3}+2x\sqrt{x+3}=9\)
25 tháng 11 2019 lúc 21:28
giải pt
a) sqrt{2x+3}+sqrt{4-x}6x-3left(sqrt{2x+3}-sqrt{4-x}right)^2-10
b) sqrt{4x+1}+2sqrt{1-x}+10sqrt{-4x^2+3x+1}13
c) left(x^2+1right)^213-xsqrt{2x^2+4}
d) left(sqrt{x+1}+sqrt{x-1}right)^2-3frac{1}{sqrt{x+1}-sqrt{x-1}}
e) left(frac{2x-3}{sqrt{x^2-1}}+2right)left(frac{1}{sqrt{x-1}}-frac{1}{sqrt{x+1}}right)frac{1}{x^2-1}
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giải pt
a) \(\sqrt{2x+3}+\sqrt{4-x}=6x-3\left(\sqrt{2x+3}-\sqrt{4-x}\right)^2-10\)
b) \(\sqrt{4x+1}+2\sqrt{1-x}+10\sqrt{-4x^2+3x+1}=13\)
c) \(\left(x^2+1\right)^2=13-x\sqrt{2x^2+4}\)
d) \(\left(\sqrt{x+1}+\sqrt{x-1}\right)^2-3=\frac{1}{\sqrt{x+1}-\sqrt{x-1}}\)
e) \(\left(\frac{2x-3}{\sqrt{x^2-1}}+2\right)\left(\frac{1}{\sqrt{x-1}}-\frac{1}{\sqrt{x+1}}\right)=\frac{1}{x^2-1}\)
\begin{cases}
x+\sqrt{x(x^2-3x+3)}=\sqrt[3]{y+2}+\sqrt{y+3}+1 & \\
3\sqrt{x-1}-\sqrt{x^2-6x+6}=\sqrt[3]{y+2}+1
\end{cases}
\begin{cases}
y^2+x^3-x^2+2\sqrt[3]{y^4}+\sqrt[3]{y^2}=2x\sqrt{x-1}(y+\sqrt[3]{y}) & \\
y^4+\sqrt{y^3-y^2+1}=y(x-1)^3+1
\end{cases}