\(\sqrt{17+12\sqrt{2}}+\sqrt{9-4\sqrt{2}}=\sqrt{8+2.2\sqrt{2}.3+9}+\sqrt{8-2.2\sqrt{2}.1+1}=\sqrt{\left(2\sqrt{2}+3\right)^2}+\sqrt{\left(2\sqrt{2}-1\right)^2}=\left|2\sqrt{2}+3\right|+\left|2\sqrt{2}-1\right|=2\sqrt{2}+3+2\sqrt{2}-1=4\sqrt{2}+2\)
\(\sqrt{17+12\sqrt{2}}+\sqrt{9-4\sqrt{2}}=\sqrt{8+2.2\sqrt{2}.3+9}+\sqrt{8-2.2\sqrt{2}.1+1}=\sqrt{\left(2\sqrt{2}+3\right)^2}+\sqrt{\left(2\sqrt{2}-1\right)^2}=\left|2\sqrt{2}+3\right|+\left|2\sqrt{2}-1\right|=2\sqrt{2}+3+2\sqrt{2}-1=4\sqrt{2}+2\)
\(\sqrt{17-12\sqrt{2}+\sqrt{9-4\sqrt{2}}}\)
Bài 1 : Rút gọn
a) \(\dfrac{2\sqrt{3}+2}{4\sqrt{3}+4}\) b) \(\dfrac{\sqrt{10}+\sqrt{15}}{\sqrt{8}+\sqrt{12}}\) c) \(\dfrac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+\sqrt{16}}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\) d) \(\sqrt{9+\sqrt{17}}\). \(\sqrt{9-\sqrt{17}}\)
Thực hiện phép tính:
\(1,\left(\sqrt{12}-2\sqrt{75}\right).\sqrt{3}\)
\(2,\sqrt{3}.\left(\sqrt{12}.\sqrt{27}-\sqrt{3}\right)\)
\(3,\left(7\sqrt{48}+3\sqrt{27}-2\sqrt{12}\right):\sqrt{3}\)
\(4,\left(\sqrt{\dfrac{1}{7}}-\sqrt{\dfrac{16}{7}}+\sqrt{7}\right):\sqrt{7}\)
\(5,\sqrt{\sqrt{5}+2}.\sqrt{\sqrt{5}-2}\)
\(6,\sqrt{9-\sqrt{17}}.\sqrt{9+\sqrt{17}}\)
thực hiện phép tính
\(\sqrt{17-12\sqrt{2}}+\sqrt{9+4\sqrt{2}}\)
Thực hiện các phép tính sau:
b) \(\sqrt{7-2\sqrt{10}}-\sqrt{7+2\sqrt{10}}\)
e) \(\sqrt{17-12\sqrt{2}}+\sqrt{9+4\sqrt{2}}\)
f) \(\sqrt{6-4\sqrt{2}}+\sqrt{22-12\sqrt{2}}\)
Tính thu gọn :
a , \(\sqrt{17-12\sqrt{2}}-\sqrt{17+12\sqrt{2}}\)
b , \(\sqrt{27+12\sqrt{5}}-\sqrt{27-12\sqrt{5}}\)
c , \(\sqrt{15-6\sqrt{6}}+\sqrt{15+\sqrt{6\sqrt{6}}}\)
d , \(\sqrt{4+\sqrt{15}}+\sqrt{4-\sqrt{15}}-2\sqrt{3-\sqrt{5}}\)
e , \(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}\)
f , \(\sqrt{5+\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
So sánh A = 2\(\sqrt{1}+2\sqrt{3}+2\sqrt{5}+2\sqrt{7}+2\sqrt{9}+2\sqrt{11}+2\sqrt{13}+2\sqrt{15}+2\sqrt{17}+2\sqrt{19}\) và B = \(2\sqrt{2}+2\sqrt{4}+2\sqrt{6}+2\sqrt{8}+2\sqrt{10}+2\sqrt{12}+2\sqrt{14}+2\sqrt{16}+2\sqrt{18}+2\sqrt{20}\)
Tính
1/ \(\sqrt{17-4\sqrt{9+4\sqrt{5}}}\)
2/ \(\sqrt{17-6\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
3/ \(\sqrt{3+\sqrt{5-\sqrt{13+4\sqrt{3}}}}\)
4/ \(\sqrt{27+10\sqrt{2}}:\dfrac{1}{\sqrt{\left(\sqrt{2}-5\right)^2}}\)
Rút gọn:
a) \(\sqrt{24-3\sqrt{15}}-\sqrt{36-9\sqrt{15}}\)
b)\(\sqrt{2-\sqrt{3}}-\sqrt{2+\sqrt{3}}\)
c)\(\sqrt{3-\sqrt{5}}-\sqrt{3+\sqrt{5}}\)
d) \(\sqrt{9-\sqrt{17}}-\sqrt{9+\sqrt{17}}\)
e) \(\sqrt{7+\sqrt{13}}-\sqrt{7-\sqrt{13}}\)
f) \(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)