\(\dfrac{x}{3}=\dfrac{3}{4x}\Leftrightarrow4x^2=9\Leftrightarrow x^2=\dfrac{9}{4}\Leftrightarrow x=\dfrac{3}{2}\left(x>0\right)\)
Ta có :
`x/3=3/(4x)``=>4x.x=3.3``=>4x^2=9``=>x^2=9/4``=>x=3/2`
Cho hỏi là \(\dfrac{x}{3} = \dfrac{3}{4x} hay \dfrac{x}{3} = \dfrac{3}{4}x\)
Nếu là cái thứ nhất: \(\dfrac{x}{3} = \dfrac{3}{4x}\)
=> 4xx = 3.3
=> 4x2 = 9
=> x2 = \(\dfrac{9}{4} \)= 2,25 => x =\(\sqrt{2,25}\)= 1,5