Ta có : \(\left(\sqrt{5}+\sqrt{7}\right)^2=5+7+2\sqrt{35}\)
=\(12+2\sqrt{35}\le12+2\sqrt{36}=12+2.6=24\)
Mà \(\left(2\sqrt{6}\right)^2=24\)
Do đó \(\left(\sqrt{5}+\sqrt{7}\right)^2< \left(2\sqrt{6}\right)^2\)
Mà \(\sqrt{5}+\sqrt{7}>0\) và \(2\sqrt{6}>0\)
Vậy \(\sqrt{5}+\sqrt{7}< 2\sqrt{6}\)
So sanh :
A=\(\sqrt[3]{2017}+\sqrt[3]{2019}\) va B=\(2\sqrt[3]{2018}\)
So sánh: \(\sqrt{6+2\sqrt{5}}-\sqrt{5}\) và \(\sqrt[3]{7+5\sqrt{2}-\sqrt{2}}\)
1.Giai pt bang cach dat an phu :
a, 3x + 14 + 5\(\sqrt{x-2}\) = 7(\(\sqrt{x+1}+\sqrt{x^2-x-2}\) )
b, 7\(\sqrt{3x-7}\) +(4x-7)\(\sqrt{7-x}\) =32
Giai phuong trinh
1/ \(\sqrt{x-3}+\sqrt{2-x}=5\)
2/ \(2x+7\sqrt{x}+\dfrac{7}{\sqrt{x}}+\dfrac{2}{x}+9=0\)
3/ \(x+\dfrac{1}{x}-4\sqrt{x}-\dfrac{4}{\sqrt{x}}+6=0\)
4/ \(\sqrt{x+9}=5-\sqrt{x-2}\)
So sánh 2 số: \(R=\dfrac{3+\sqrt{5}}{2\sqrt{2}+\sqrt{3+\sqrt{5}}}+\dfrac{3-\sqrt{5}}{2\sqrt{2}-\sqrt{3-\sqrt{5}}}\)
\(S=\dfrac{4+\sqrt{7}}{3\sqrt{2}+\sqrt{4+\sqrt{7}}}+\dfrac{4-\sqrt{7}}{3\sqrt{2}-\sqrt{4-\sqrt{7}}}\)
So sánh 2 số: \(R=\dfrac{3+\sqrt{5}}{2\sqrt{2}+\sqrt{3+\sqrt{5}}}+\dfrac{3-\sqrt{5}}{2\sqrt{2}-\sqrt{3-\sqrt{5}}}\)
\(S=\dfrac{4+\sqrt{7}}{3\sqrt{2}+\sqrt{4+\sqrt{7}}}+\dfrac{4-\sqrt{7}}{2\sqrt{2}-\sqrt{3-\sqrt{5}}}\)
giai phuong trinh sau:
\(x+\sqrt{x+\frac{1}{2}+\sqrt{x+\frac{1}{4}}+\frac{1}{4}}=2\)
m.m giup minh cau nay aj. thank m.n
So sánh
\(\sqrt{4+\sqrt{7}-}\sqrt{4-\sqrt{7}}va\sqrt{3}\)
1. So sánh:
\(\sqrt{13}-\sqrt{12}\)và \(\sqrt{7}-\sqrt{6}\)
2. Giải pt:
\(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-\sqrt{2x-5}}=2\sqrt{2}\)
