Có : \(B=\sqrt{12+\sqrt{12+...+\sqrt{12+\sqrt{12}}}}\)
\(B< \sqrt{12+\sqrt{12+...+\sqrt{12+\sqrt{16}}}}\)
.......
= \(\sqrt{12+4}=\sqrt{16}=4\)
=> \(B=\sqrt{12+\sqrt{12+...+\sqrt{12+\sqrt{12}}}}\) < 4
Có : \(B=\sqrt{12+\sqrt{12+...+\sqrt{12+\sqrt{12}}}}\)
\(B< \sqrt{12+\sqrt{12+...+\sqrt{12+\sqrt{16}}}}\)
.......
= \(\sqrt{12+4}=\sqrt{16}=4\)
=> \(B=\sqrt{12+\sqrt{12+...+\sqrt{12+\sqrt{12}}}}\) < 4
Bài 1: Tính
\(\sqrt{3+2\sqrt{3}}-\sqrt{4-2\sqrt{3}}\\ \sqrt{12+6\sqrt{3}+\sqrt{12-6\sqrt{3}}}\\ \sqrt{9-4\sqrt{2}+\sqrt{9+4\sqrt{2}}}\)
\(\sqrt{\sqrt{2}+2+\sqrt{4+\sqrt{9-\sqrt{32}}}}\\ \sqrt{6+2\sqrt{5}-\sqrt{29+12\sqrt{5}}}\\ \sqrt{8+\sqrt{8}+\sqrt{20}+\sqrt{40}}-\sqrt{\sqrt{49}+\sqrt{40}}\\ \sqrt{4+\sqrt{5\sqrt{3}+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}\)
1)\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
2)\(\sqrt{35+12\sqrt{6}}-\sqrt{35-12\sqrt{6}}\)
3)\(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
thực hiện phép tính
a)\(\sqrt{6+2\sqrt{5}}-\sqrt{62\sqrt{5}}\)
b)\(\sqrt{24-8\sqrt{5}}+\sqrt{9-4\sqrt{5}}\)
c) \(\sqrt{6-4\sqrt{2}}+\sqrt{22-12\sqrt{2}}\)
d)\(\sqrt{41+12\sqrt{5}}-\sqrt{46-6\sqrt{ }5}\)
e)\(\sqrt{17-12\sqrt{2}}+\sqrt{9+4\sqrt{2}}\)
f)\(\sqrt{17-12\sqrt{2}}+\sqrt{9+4\sqrt{2}}\)
g) \(\sqrt{43+24\sqrt{3}}-\sqrt{49-8\sqrt{3}}\)
So sánh :
a) A= \(\sqrt{\dfrac{37}{4}-\sqrt{49+12\sqrt{5}}}\) ; B= \(\sqrt{5}-\dfrac{3}{2}\)
b)C=\(\dfrac{16\sqrt{36}-20\sqrt{48}+10\sqrt{3}}{\sqrt{12}}\) và B =\(16\sqrt{3}-36\)
c) A=\(\sqrt{2015}+\sqrt{2017}\) và B=\(2\sqrt{2016}\)
a, \(\sqrt{\sqrt{3}-\sqrt{1-\sqrt{21-12\sqrt{3}}}}\)
b,\(\sqrt{13+30\sqrt{2+\sqrt{9}+4\sqrt{2}}}\)
c,\(\sqrt{5}-\sqrt{3-\sqrt{29}-12\sqrt{5}}\)
ai giúp tui với
Thực hiện phép tính:
a)\(\sqrt{4-2\sqrt{3}}+\sqrt{4+2\sqrt{3}}\)
b)\(\sqrt{24+8\sqrt{5}}+\sqrt{9-4\sqrt{5}}\)
c)\(\sqrt{17-12\sqrt{2}}+\sqrt{9+4\sqrt{2}}\)
d)\(\sqrt{6-4\sqrt{2}}+\sqrt{22-12\sqrt{2}}\)
rút gọn
a, \(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
b\(\sqrt{3+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
thankyou các bạn trước
Rút gọn :
\(\dfrac{\sqrt{3-2\sqrt{2}}}{\sqrt{17-12\sqrt{2}}}-\dfrac{\sqrt{3+2\sqrt{2}}}{\sqrt{17+12\sqrt{2}}}\)
\(a,\sqrt{3+2\sqrt{2}}-\sqrt{2}\)
\(b,\sqrt{16-6\sqrt{7}}-2\sqrt{7}\)
\(c,\sqrt{30+12\sqrt{6}}+\sqrt{30-12\sqrt{6}}\)
\(d,\sqrt{9-4\sqrt{5}}-\sqrt{5}\)
\(e,\sqrt{\left(-2\right)^6}+\sqrt{\left(-3\right)^4}\)