(3-x)(x+2)>0 (x thuộc Z)
<=>\(\left[\begin{matrix}\left\{\begin{matrix}3-x>0\\x+2>0\end{matrix}\right.\\\left\{\begin{matrix}3-x< 0\\x+2< 0\end{matrix}\right.\end{matrix}\right.\)
<=>\(\left[\begin{matrix}\left(1\right)\left\{\begin{matrix}x< 3\\x>-2\end{matrix}\right.\\\left(loại\right)\left\{\begin{matrix}x>3\\x< -2\end{matrix}\right.\end{matrix}\right.\)
(1) <=> -2<x<3
<=> x max = 2 (tm x thuộc Z)
vậy x=2