\(\left(2x-3\right)\left(x^2-9\right)=0\)
\(\Leftrightarrow\left(2x-3\right) \left(x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}2x-3=0\\x-3=0\\x+3=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{3}{2}\\x=3\\x=-3\end{array}\right.\)
= 3 giá trị
( x= 3//; -3;3) nếu ghi vào bài thi viết số 3 dc rùi
còn bai nao ,mk giup, sap ra v4 rui, mk thi rui 300đ
\(\left(2x-3\right)\left(x^2-9\right)\)
\(\Leftrightarrow\left[\begin{matrix}2x-3=0\\x^2-9=0\end{matrix}\right.\)
\(\Leftrightarrow\left[\begin{matrix}x=\frac{3}{2}\\x=\pm3\end{matrix}\right.\)