\(\left(sinx+cosx\right)^2=\frac{25}{16}\Leftrightarrow sin^2x+cos^2x+2sinx.cosx=\frac{25}{16}\)
\(\Rightarrow sinx.cosx=\frac{\frac{25}{16}-1}{2}=\frac{9}{32}\)
\(B=sin^3x+cos^3x=\left(sinx+cosx\right)^3-3sinx.cosx\left(sinx+cosx\right)=\frac{115}{128}\)