Question

rút gọn biểu thức

\(\frac{\text{x( x - 3 ) - 2x + 6}}{x^2-2x}\)

 

Answer 1

\(\frac{x\left(x-3\right)-2x+6}{x^2-x}=\frac{x^2-3x-2x+6}{x\left(x-2\right)}=\frac{\left(x^2-2x\right)-\left(3x-6\right)}{x\left(x-2\right)}\)

\(=\frac{x\left(x-2\right)-3\left(x-2\right)}{x\left(x-2\right)}=\frac{\left(x-3\right)\left(x-2\right)}{x\left(x-2\right)}=\frac{x-3}{x}\)

Answer 2

\(\frac{x\left(x-3\right)-2x+6}{x^2-2x}\)

=\(\frac{x\left(x-3\right)-2\left(x-3\right)}{x\left(x-2\right)}\)

=\(\frac{\left(x-2\right)\left(x-3\right)}{x\left(x-2\right)}\)

=\(\frac{x-3}{x}\)

CHÚC BẠN HỌC TỐT!

Answer 3

\(\frac{x\left(x-3\right)-2x+6}{x^2-2x}=\frac{x\left(x-3\right)-2\left(x+3\right)}{x\left(x-2\right)}=\frac{\left(x-2\right)\left(x-3\right)\left(x+3\right)}{x\left(x-2\right)}=\frac{\left(x-2\right)\left(x^2-3^2\right)}{x\left(x-2\right)}=\frac{x^2-9}{x}=\frac{x-9}{1}=x-9\)

Answer 4

đề là rút gọn phân thức nhé