Question

Phân tích đa thức thành nhân tử:

\(x^5+x+1\)

:PPPPPPPPPPPP

Answer 1

Âm sm r` trả nick t đi tml

\(x^5+x+1\)

\(=x^5-x^4+x^2+x^4-x^3+x+x^2+x+1\)

\(=x^2\left(x^3-x^2+1\right)+x\left(x^3-x^2+1\right)+\left(x^3-x^2+1\right)\)

\(=\left(x^2+x+1\right)\left(x^3-x^2+1\right)\)

Answer 2

\(x^5+x+1\)

\(=x^5+x^4+x^3+x^2-x^4-x^3-x^2+x+1\)

\(=x^3\left(x^2+x+1\right)+\left(x^2+x+1\right)-x^4-x^3-x^2_{ }\)

\(=x^3\left(x^2+x+1\right)+\left(x^2+x+1\right)-x^2\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^3-x^2+1\right)\)