Question

Phân tích đa thức thành nhân tử

a)\(a^3+3a^2+3a+1-27b^3\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \)

b)\(64x^3y+\dfrac{1}{4}yz^3\)

c)\(x^6-x^4+2x^3+2x^2\)

d)\(2x^3-x^2-1\)

Các bạn giúp mik nhé mik đang cần gấp

Answer 1

\(a,a^3+3a^2+3a+1-27b^3\\ =\left(a+1\right)^3-\left(3b\right)^3\\ =\left(a+1-3b\right)\left[\left(a+1\right)^2+\left(a+1\right)\left(3b\right)+\left(3b\right)^2\right]\\ =\left(a+1-3b\right)\left(a^2+2a+1+3ab+3b+9b^2\right)\)

\(c,x^6-x^4+2x^3+2x^2\\ =x^4\left(x^2-1\right)+2x^2\left(x+1\right)\\ =x^4\left(x+1\right)\left(x-1\right)+2x^2\left(x+1\right)\\ =x^2\left(x+1\right)\left[x^2\left(x-1\right)+2\right]\\ =x^2\left(x+1\right)\left(x^3-x^2+2\right)\)