Question

phân tích đa thức thành nhân tử

a, 25-(x-y)^2

b,a^4-1

Answer 1

\(25-\left(x-y\right)^2=\left(5-x+y\right)\left(5+x-y\right)\)

\(a^4-1=\left(a^2-1\right)\left(a^2+1\right)=\left(a-1\right)\left(a+2\right)\left(a^2+1\right)\)

Answer 2

\(a,25-\left(x-y\right)^2\)

\(=5^2-\left(x-y\right)^2\)

\(=\left[5-\left(x-y\right)\right].\left[5+\left(x-y\right)\right]\)

\(=\left(5-x+y\right).\left(5+x-y\right)\)

\(b,a^4-1\)

\(=\left(a^2\right)^2-1^2\)

\(=\left(a^2-1\right)\left(a^2+1\right)\)

\(=\left(a-1\right)\left(a+1\right)\left(a^2+1\right)\)

Chúc bạn hok tốt!!!