Question

phân tích đa thức sau thành nhân tử:

\(2x^3-x^2+5x+3\)

Answer 1

\(2x^3-x^2+5x+3=2x^3+x^2-2x^2-x+6x+3\)

\(=x^2\left(2x+1\right)-2x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x^2-2x+3\right)\)

Answer 2

\(A=2x^2\left(x+\dfrac{1}{2}\right)-2x\left(x+\dfrac{1}{2}\right)+6\left(x+\dfrac{1}{2}\right)\)

\(=\left(2x^2-2x+6\right)\left(x+\dfrac{1}{2}\right)=2\left(x^2-x+6\right)\left(x+\dfrac{1}{2}\right)\)

Ko hiểu gì hỏi lại.

Answer 3

2x^3-x^2+5x+3

=2x^3+x^2-2x^2-x+6x+3

=x^2(2x+1)-x(2x+1)+3(2x+1)

=(2x+1)(x^2-x+3)