Câu 1:
a: \(\sqrt{4x-8}=2\)
\(\Leftrightarrow4x-8=4\)
hay x=3
b: \(\sqrt{\dfrac{1}{2}x+4}=\dfrac{2}{3}\)
\(\Leftrightarrow x\cdot\dfrac{1}{2}+4=\dfrac{4}{9}\)
\(\Leftrightarrow x\cdot\dfrac{1}{2}=\dfrac{4}{9}-4=\dfrac{-32}{9}\)
hay \(x=-\dfrac{16}{9}\)