Ta có: \(\frac{1}{2}a=2b\Rightarrow a=4b\)
\(\frac{9}{8}a=kb\)
\(\Rightarrow\frac{9}{8}.4.b=kb\)
\(\Rightarrow\frac{36}{8}b=kb\)
\(\Rightarrow k=\frac{36}{8}\)
Vậy \(k=\frac{36}{8}\)
\(\frac{1}{2}a=2b\Rightarrow\frac{1}{8}a=\frac{1}{2}b=>\frac{9}{8}a=\frac{9}{2}b=>k=\frac{9}{2}\)