Question

Mong các bạn giúp.

Tìm x trong các tỉ lệ thức sau.

a) x : 2,4=3,5 : 0,7

b)\(2\frac{1}{5}:\)x= \(-3\frac{1}{4}:\left(-2\frac{2}{5}\right)\)

c) 4,8 : 0,16 = x : 0,4

Cảm ơn các bạn nhiều.💟💟💟💟

Answer 1

a) \(x:2,4=3,5:0,7\)

=> \(x:2,4=5\)

=> \(x=5.2,4\)

=> \(x=12\)

Vậy \(x=12.\)

b) \(2\frac{1}{5}:x=-3\frac{1}{4}:\left(-2\frac{2}{5}\right)\)

=> \(\frac{11}{5}:x=-\frac{13}{4}:\left(-\frac{12}{5}\right)\)

=> \(\frac{11}{5}:x=\frac{65}{48}\)

=> \(x=\frac{11}{5}:\frac{65}{48}\)

=> \(x=\frac{528}{325}\)

Vậy \(x=\frac{528}{325}.\)

c) \(4,8:0,16=x:0,4\)

=> \(30=x:0,4\)

=> \(x=30.0,4\)

=> \(x=12\)

Vậy \(x=12.\)

Chúc bạn học tốt!

Answer 2

\( a)x:2,4 = 3,5:0,7\\ \Leftrightarrow x:2,4 = 5\\ \Leftrightarrow x = 5 \times 2,4\\ \Leftrightarrow x = 12\\ b)2\dfrac{1}{5}:x = - 3\dfrac{1}{4}:\left( { - 2\dfrac{2}{5}} \right)\\ \Leftrightarrow \dfrac{{11}}{5}:x = \dfrac{{ - 13}}{4}:\dfrac{{ - 12}}{5}\\ \Leftrightarrow \dfrac{{11}}{5}:x = \dfrac{{65}}{{48}}\\ \Leftrightarrow x = \dfrac{{11}}{5}:\dfrac{{65}}{{48}}\\ \Leftrightarrow x = \dfrac{{528}}{{325}}\\ c)4,8:0,16 = x:0,4\\ \Leftrightarrow 30 = x:0,4\\ \Leftrightarrow x = 30 \times 0,4\\ \Leftrightarrow x = 12 \)

Answer 3

a,\(\frac{x}{2,4}=\frac{3,5}{0,7}\)

=> x= \(\frac{2,4.3,5}{0,7}\)

=>x=12

b,\(2\frac{1}{5}:x=-3\frac{1}{4}:\left(-2\frac{2}{5}\right)\)

=>\(\frac{11}{5}\):x =\(\frac{-11}{4}\):\(\frac{-8}{5}\)

=>\(\frac{11}{5}\):x=\(\frac{11}{8}\)

=>x=\(\frac{8}{5}\)

c,4,8 :0,16=x:0,4

=>x=\(\frac{4,8.0,4}{0,16}\)

=>x= 12