\(\lim\limits_{x\rightarrow-3}\dfrac{-x^2-x-6}{x^2-9}\)
\(=-\infty\) vì \(\left\{{}\begin{matrix}\lim\limits_{x\rightarrow-3}-x^2-x-6=-\left(-3\right)^2-\left(-3\right)-6=-12< 0\\\lim\limits_{x\rightarrow-3}x^2-9=\left(-3\right)^2-9=0\end{matrix}\right.\)