\(\left(z-\dfrac{2}{15}\right)^3=\dfrac{8}{125}\)
\(\left(z-\dfrac{2}{15}\right)^3=\left(\dfrac{2}{5}\right)^3\)
\(\Rightarrow z-\dfrac{2}{15}=\dfrac{2}{5}\)
\(z=\dfrac{2}{5}+\dfrac{2}{15}\)
\(z=\dfrac{8}{15}\)
Ta có: \(\left(z-\dfrac{2}{15}\right)^3=\dfrac{8}{125}\)
\(\Leftrightarrow\left(z-\dfrac{2}{15}\right)^3=\left(\dfrac{2}{5}\right)^3\)
\(\Leftrightarrow z-\dfrac{2}{15}=\dfrac{2}{5}\)
\(\Leftrightarrow z=\dfrac{2}{5}+\dfrac{2}{15}=\dfrac{6}{15}+\dfrac{2}{15}\)
hay \(z=\dfrac{8}{15}\)
Vậy: \(z=\dfrac{8}{15}\)