=>x+1/3=0 hoặc 2x-16=0
=>x=-1/3 hoặc x=4
=>x+1/3=0 hoặc 2x-16=0
=>x=-1/3 hoặc x=4
Tìm x biết :
a) \(x^2-3=1\)
b) \(2x^3+12=-4\)
c) \(\left(2x-3\right)^2=16\)
d) \(x:\left(\dfrac{-1}{2}\right)^1=\dfrac{-1}{2}\)
h) \(\left(\dfrac{1}{4}-x\right)^2=\dfrac{25}{16}\)
i) \(\left(x+\dfrac{1}{3}\right)^3=\dfrac{-1}{8}\)
k) \(\left(\dfrac{1}{2}-x\right)^2=1\)
tìm x\(\in\)Q biết rằng
a)\(\left(x-\dfrac{1}{2}\right)^2=0\)
b)\(\left(x-2\right)^2=1\)
c)\(\left(2x-1\right)^3=-8\)
d)\(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)
tìm x biết
a)\(\left(x-\dfrac{1}{3}\right)\times\left(x+\dfrac{2}{3}\right)\)>0
b)\(\left(x+\dfrac{3}{5}\right)\times\left(x+1\right)\)<0
Tìm \(x\in\mathbb{Q}\), biết rằng :
a) \(\left(x-\dfrac{1}{2}\right)^2=0\)
b) \(\left(x-2\right)^2=1\)
c) \(\left(2x-1\right)^3=-8\)
d) \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)
1. Tìm x biết:
a) \(\left(x+36\right)^2=1936\)
b) \(\dfrac{3}{5}^{x+2}=\dfrac{81}{625}\)
c) \(2005^{\left(2x-1\right)\left(2+3x\right)}=1\)
d) \(\left(\dfrac{9}{16}\right)^{x-5}=\left(\dfrac{4}{3}\right)^4\)
e) \(\left(\dfrac{3}{5}\right)^x.\left(\dfrac{125}{72}\right)^5=\dfrac{81}{625}\)
2. a) Tìm x biết:
\(\left(3x+1\right)^4=\left(3x-1\right)^2\)
b) Có số hữu tỉ x thõa mản đẳng thức
\(\left(3x+1\right)^4+\left(3x-1\right)^2=0\)
3. Tính giá trị của biểu thức:
\(A=\left\{-\left[-\left(\dfrac{1}{x}\right)^2\right]^3\right\}^5.\left\{-\left[-\left(-x\right)^5\right]^2\right\}^3\) ( \(x\notin0\)
4. Tìm các cặp số (x,y) thõa mản các đk sau:
a) \(x\left(x+y\right)=\dfrac{5}{12}\) và \(y\left(x+y\right)=\dfrac{5}{18}\)
b) \(x\left(x-y\right)=\dfrac{2}{45}\) và \(y\left(x-y\right)=\dfrac{1}{25}\)
Mai nộp rồi còn 4 bài đó ( help me )
a) \(x:\left(-\dfrac{1}{2}\right)^3=-\dfrac{1}{2}\)
b)\(\left(\dfrac{3}{4}\right)^2.x=\left(\dfrac{3}{4}\right)^5\)
bài 1 tính
a/ \(\left|1\dfrac{1}{2}-2\dfrac{1}{3}\right|^2+\left|1-\dfrac{5}{4}\right|\)
b/\(\left|\left(-1\right)^{100}-2\dfrac{1}{3}\right|+\dfrac{5}{6}\)
c/\(\left|\left(\dfrac{2}{3}\right)^{-1}-\dfrac{7}{4}\right|-\dfrac{7}{4}\)
d/ \(\left|x-5\right|+\left|x-8\right|\) với 5 \< x>/
1. Tính:
C= \(\left(\dfrac{1}{2^2-1}\right)\left(\dfrac{1}{3^2-1}\right)\left(\dfrac{1}{4^2-1}\right).....\left(\dfrac{1}{100^2-1}\right)\)
2. Tìm x:
\(\left(\dfrac{2}{5}\right)^x>\left(\dfrac{5}{2}\right)^{-3}.\left(\dfrac{-2}{5}\right)^2\)
Help me!!!
Bài 1:Tính
a)\(\left(\dfrac{3}{7}+\dfrac{1}{2}\right)^2\) b)\(\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)c) \(\dfrac{5^4.20^4}{25^5.4^5}\)
Bài 2:Tìm x
a)\(\left(x-\dfrac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\)
b)\(\left(x+5\right)^3=-64\) c)\(\left(2x-3\right)^2=9\)
c)\(x^2+1=82\)
Bài 3:Tính
M=\(\dfrac{8^{10}+4^{10}}{8^4+4^{11}}\)
Bài 4:So sánh \(2^{24}\)và\(3^{16}\)
GIÚP MIK DZỚI,MÌNH TIK CHO ><
Tìm x,y biết
a.\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+1}=0\)
b.\(\dfrac{5x-1}{3}=\dfrac{7y-6}{5}=\dfrac{5x+7y-7}{4x}\)
c.\(\left|x+5\right|+\left(3y-4\right)^{2017}=0\)