\(\left(x-1\right)^2=121\)
\(\Rightarrow\left[\begin{array}{nghiempt}x-1=11\\x-1=-11\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=12\\x=-10\end{array}\right.\)
Vậy \(x=\left\{12;-10\right\}\)
\(\left(x-1\right)^2=121\)
\(\left(x-1\right)^2=11^2\)
\(\Rightarrow x-1=\pm11\)
Nếu x - 1 = 11 thì x = 12
Nếu x - 1 = -11 thì x = -10
Vậy x = 12 hoặc x = -10
( x - 1 ) 2 = 121
=> ( x - 1 ) 2 = 112
=> x - 1 = 11
=> x = 11 + 1
=> x = 12
\(\left(x-1\right)^2=121\)
\(\Leftrightarrow x-1=11\)
\(\Leftrightarrow x=12\)
\(\left(x-1\right)^2=121\)
\(\Rightarrow\left(x-1\right)^2=11^2\)
\(\Rightarrow\left(x-1\right)=11\)
\(\Rightarrow x=11-1\)
\(\Rightarrow x=10\)
(x-1)2=121
\(\Rightarrow\)(x-1)2=112
\(\Rightarrow\)(x-1)=11
\(\Rightarrow\)x-1=11
\(\Rightarrow\)x=11-1
\(\Rightarrow\)x=10
(x-1)2=121
(x-1)2=112
(x-1)=11
x-1=11
x=11+1
x=12
Mik làm thiếu 1 trường hợp . Silver bullet làm đủ và đúng hơn mik
