Question

BT1: Tính

1) \(\dfrac{7}{80}:\dfrac{\left(-7\right)}{4}-\dfrac{2}{9}:\left(8-\dfrac{8}{3}\right)-\dfrac{\left(-5\right)}{24}.\left(\dfrac{\left(-10\right)}{3}+\dfrac{38}{15}\right)^2\)

2) 1500 - {5\(^3\) . 2\(^3\)- 11 . [ 7\(^2\) - 5. 2\(^3\) + 8 ( 11\(^2\) - 121)]}

Answer 1

1: \(=-\dfrac{7}{80}\cdot\dfrac{4}{7}-\dfrac{2}{9}:\dfrac{16}{3}+\dfrac{5}{24}\cdot\left(\dfrac{-50+38}{15}\right)^2\)

\(=\dfrac{-1}{20}-\dfrac{2}{9}\cdot\dfrac{3}{16}+\dfrac{5}{24}\cdot\dfrac{16}{25}\)

\(=\dfrac{-1}{20}-\dfrac{1}{24}+\dfrac{2}{15}\)

\(=\dfrac{-6-5+16}{120}=\dfrac{5}{120}=\dfrac{1}{24}\)

2: \(=1500-\left\{10^3-11\cdot\left[49-5\cdot8\right]\right\}\)

\(=1500-\left\{1000-11\cdot9\right\}\)

\(=1500-1000+99=599\)