Question

Câu 1 : Tìm x :

a) \(\left(-11\right)^2-15.\left(x-2\right)=134-16x\)

b) \(\left(4x+1\right)\left(x^2-16\right)=0\)

c) \(-2\left(x-3\right)+\left(-2\right)^2=4-3x\)

Answer 1

a) (−11)² − 15(x − 2) = 134 − 16x

121 - 15x + 30 = 134 - 16x

16x - 15x = 134 - 121 - 30

x = -17

b) (4x + 1)(x² − 16)=0

(4x + 1)(x - 4)(x + 4) = 0

\(\left[\begin{matrix}4x+1=0\\x-4=0\\x+4=0\end{matrix}\right.\)

\(\left[\begin{matrix}4x=-1\\x=4\\x=-4\end{matrix}\right.\)

\(\left[\begin{matrix}x=-\frac{1}{4}\\x=4\\x=-4\end{matrix}\right.\)

c) − 2(x − 3) + (− 2)² = 4 − 3x

3x + 4 - 2x + 6 = 4

x = 4 - 4 - 6

x = - 6

Answer 2

Nguyễn Huy TúPhương An