Question

\(\left(\dfrac{x^2}{y^2}+\dfrac{x}{y}\right):\left(\dfrac{x}{y^2}-\dfrac{1}{y}+\dfrac{1}{x}\right)\)

giải dúp đi mn ui

Answer 1

\(\left(\dfrac{x^2}{y^2}+\dfrac{x}{y}\right):\left(\dfrac{x}{y^2}-\dfrac{1}{y}+\dfrac{1}{x}\right)=\dfrac{x^2+xy}{y^2}\cdot\dfrac{xy^2}{x^2-xy+y^2}=\dfrac{x^3+x^2y}{x^2-xy+y^2}\)

Answer 2

\(\left(\dfrac{x^2}{y^2}+\dfrac{x}{y}\right):\left(\dfrac{x}{y^2}-\dfrac{1}{y}+\dfrac{1}{x}\right)=\left(\dfrac{x^2}{y^2}+\dfrac{xy}{y^2}\right):\left(\dfrac{x^2}{xy^2}-\dfrac{xy}{xy^2}+\dfrac{y^2}{xy^2}\right)\)

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