Question

làm tính chia
A) [(3x^2y - 6x^3y^2) : 3xy + (3xy - 1)x]^2 : 0,5x^2
b) [7(a-b)^5 + 5(a-b)^3] : (b-a)^2
c) [7(a-3b)^3 + (a-3b)] : (2a-6b)

Answer 1

a: \(=\left[\dfrac{3xy\left(x-2x^2y\right)}{3xy}+6x^2y-x\right]^2:\dfrac{1}{2}x^2\)

\(=\left[x-2x^2y+6x^2y-x\right]^2:\dfrac{1}{2}x^2\)

\(=\dfrac{16x^4y^2}{0.5x^2}=32x^2y^2\)

b: \(=\dfrac{7\left(a-b\right)^5+5\left(a-b\right)^3}{\left(a-b\right)^2}=7\left(a-b\right)^3+5\left(a-b\right)\)

c: \(=\dfrac{7\left(a-3b\right)^3+\left(a-3b\right)}{2\left(a-3b\right)}=\dfrac{7\left(a-3b\right)^2+1}{2}\)