Question

Làm tính chia :

a) \(\left(-2x^5+3x^2-4x^3\right):2x^2\)

b) \(\left(x^3-2x^2y+3xy^2\right):\left(-\dfrac{1}{2}x\right)\)

c) \(\left(3x^2y^2+6x^2y^3-12xy\right):3xy\)

Answer 1

Bài giải:

a) (-2x⁵ + 3x² – 4x³) : 2x² = (- $\frac{2}{2}$)x^{5 – 2} + $\frac{3}{2}$x^{2 – 2} + (-$\frac{4}{2}$)x^{3 – 2} = - x³ + $\frac{3}{2}$ – 2x.

b) (x³ – 2x²y + 3xy²) : (- $\frac{1}{2}$x) = (x³ : -$\frac{1}{2}$x) + (-2x²y : -$\frac{1}{2}$x) + (3xy² : -$\frac{1}{2}$x)

= -2x² + 4xy – 6y²

c)(3x²y² + 6x²y³ – 12xy) : 3xy = (3x²y² : 3xy) + (6x²y² : 3xy) + (-12xy : 3xy)

= xy + 2xy² – 4.

Answer 2

a) (-2x⁵+3x²-4x³) : 2x²

= (-2x⁵:2x²)-(4x³:2x²)+(3x²:2x²)

= -x³-2x+\(\dfrac{3}{2}\)

b) \(\left(x^3-2x^2y+3xy^2\right):\left(-\dfrac{1}{2}x\right)\)

= \(\left(x^3:\dfrac{-1}{2}x\right)+\left(-2x^2y:\dfrac{-1}{2}x\right)+\left(3xy^2:\dfrac{-1}{2}x\right)\)

= \(-2x^2+4xy-6y^2\)

c) \(\left(3x^2y^2+6x^2y^3-12xy\right):3xy\)

= \(\left(6x^2y^3:3xy\right)+\left(3x^2y^2:3xy\right)+\left(-12xy:3xy\right)\)

= \(xy^2+xy-4\)