Question

giúp mình vs cần gấp

x^2-4y^2-3x+6y

a^2+2ab+b^2-ac-bc

25x^2-10x-3x

16x^2+24x-7

Answer 1

a/ \(x^2-4y^2-3x+6y=\left(x^2-4y^2\right)-\left(3x-6y\right)=\left(x-2y\right)\left(x+2y\right)-3\left(x-2y\right)=\left(x-2y\right)\left(x+2y-3\right)\)

b/ \(a^2+2ab+b^2-ac-bc=\left(a^2+2ab+b^2\right)-\left(ac+bc\right)=\left(a+b\right)^2-c\left(a+b\right)=\left(a+b\right)\left(a+b-c\right)\)

c/ \(25x^2-10x-3x=25x^2-13x=x\left(25x-13\right)\)

d/ \(16x^2+24x-7=16x^2-4x+28x-7=4x\left(4x-1\right)+7\left(4x-1\right)=\left(4x-1\right)\left(4x+7\right)\)