Question

Giair phương trình sau :

 \(4-\left(x-7\right)=5\left(3x-2\right)\)

Answer 1

\(4-\left(x-7\right)=5\left(3x-2\right)\)

\(\Rightarrow4-x+7=15x-10\)

\(\Rightarrow16x=4+7+10\)

\(\Rightarrow16x=21\)

\(\Rightarrow x=\frac{21}{16}\)

Answer 2

\(4-\left(x-7\right)=5\left(3x-2\right)\)

\(\Leftrightarrow4-x+7=15x-10\)

\(\Leftrightarrow-x-15x=-10-4-7\)

\(\Leftrightarrow-16x=-21\)

\(\Leftrightarrow x=\frac{21}{16}\)

Vậy phương trình có tập nghiệm \(S=\left\{\frac{21}{16}\right\}\)