Question

Giair phương trình sau :

  \(4-\left(x-7\right)=4\left(3-2x\right)\)

Answer 1

      4-(x-7)=4(3-2x)

       4-x+7=12-8x

       11-x=12-8x

        x-8x=11-12

          -7x=-1

           \(x=\frac{1}{7}\)

         Vậy \(x=\frac{1}{7}\)

Answer 2

\(4-\left(x-7\right)=4\left(3-2x\right)\)

\(\Leftrightarrow4-x+7=12-8x\)

\(\Leftrightarrow-x+8x=12-4-7\)

\(\Leftrightarrow7x=1\)

\(\Leftrightarrow x=\frac{1}{7}\)

Vậy phương trình có tập nghiệm \(S=\left\{\frac{1}{7}\right\}\)

Answer 3

\(4-\left(x-7\right)=4\left(3-2x\right)\)

\(\Leftrightarrow4-x+7=12-8x\)

\(\Leftrightarrow-x+8x=12-4-7\)

\(\Leftrightarrow7x=1\)

\(\Leftrightarrow x=\frac{1}{7}\)