\(\left|2x-3\right|=x+1\) (1)
TH1:Nếu \(2x-3\ge0\Leftrightarrow x\ge\frac{3}{2}\)
<=>|2x-3|=2x-3
(1)<=>2x-3=x+1
=>x=4(nhận)
TH2:Nếu 2x-3<0 \(\Leftrightarrow x< \frac{3}{2}\Leftrightarrow\left|2x-3\right|=3-2x\)
(1)<=>3-2x=x+1
=>x=2/3(nhận)
npt là:S={2/3;4}
Giải pt sau
\(\left(\dfrac{x-1}{x+2}\right)^2-\left(\dfrac{2x+4}{x-3}\right)^2+3\left(\dfrac{x-1}{x-3}\right)=0\)
giải pt sau \(\left(\dfrac{x+1}{x-2}\right)^2-3\left(\dfrac{2x-4}{x-4}\right)^2+\dfrac{x+1}{x-4}=0\)
\(\left(x-1^{ }\right)^3+\left(x+3\right)^3=\left(2x+2^{ }\right)^3\)
giải pt
giải pt sau
a)\(\left(x-2\right)\left(x-3\right)+2x=\left(x-2\right)^2-2\)
b) \(\left(x-1\right)^2+3x\left(x-1\right)+7=\left(2x-1\right)^2+5\left(x-3\right)\)
c)\(5\left(x^1-2x-1\right)+2\left(3x-2\right)=5\left(x+1\right)^2\)
d)\(\left(x-1\right)\left(x^2+x+1\right)-2x=x\left(x-1\right)\left(x+1\right)\)
Giải PT sau:
1)\(\left(2x+7\right)^2=9\left(x+2\right)^2\)
2)\(\left(x^2-16\right)^2-\left(x-4\right)^2=0\)
3)\(\left(5x^2-2x+10\right)^2=\left(3x^2+10x-8\right)^2\)
1.giải các bpt sau
a.\(\left(x-3\right)\left(x+3\right)\ge x^2-7x+1\)
b.\(\dfrac{1,5-x}{5}\ge\dfrac{4x+5}{2}\)
2.giải các pt sau
\(x^3+1=x.\left(x+1\right)\)
1)Giải pt: \(2\cdot\left(x+\dfrac{1}{x}\right)^2+\left(x^2+\dfrac{1}{x^2}\right)^2-\left(x^2+\dfrac{1}{x^2}\right)\cdot\left(x+\dfrac{1}{x}\right)^2=\left(x+2\right)^2\)
2)Giải pt: \(\dfrac{|3-2x|-|x|}{|2+3x|+x-2}=5\)
3)tìm tất cả các cặp số nguyên tố(x,y) là nghiệm của pt: x2 - 2y2 - 1=0
Giải pt
a)\(\left|x-2\right|=3\)
b)\(\left|x+1\right|=\left|2x+3\right|\)
c)\(\left|3x\right|=x+6\)
Giải PT: \(x\left(x+2\right)\left(x^2+2x+2\right)+1=0\)
