\(x^3+x+10=0\)
\(\Leftrightarrow x^3-2x^2+5x+2x^2-4x+10=0\)
\(\Leftrightarrow x\left(x^2-2x+5\right)+2\left(x^2-2x+5\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x^2-2x+5\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+2=0\\x^2-2x+5=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x+2=0\\\left(x^2-2x+1\right)+4=0\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-2\\\left(x-1\right)^2+4>0\left(loai\right)\end{array}\right.\)
Vậy x=-2
x3+x+10=0
=>x3+x= -10
<=> x(x2+1)= -10
Ta xét: 2.5= 10
=>x=2
x3 + x+10=0
=>x3+x= -10
<=>x(x2+1)= -10
Ta xét: -2.5 = -10
=>x= -2
