\(\Leftrightarrow\dfrac{1}{2}-\dfrac{1}{2}cos\left(2x-\dfrac{\pi}{2}\right)=\dfrac{1}{2}+\dfrac{1}{2}cos2x\)
\(\Leftrightarrow-sin2x=cos2x\)
\(\Rightarrow tan2x=-1\)
\(\Rightarrow2x=-\dfrac{\pi}{4}+k\pi\)
\(\Rightarrow x=-\dfrac{\pi}{8}+\dfrac{k\pi}{2}\)
