\(\frac{2x+1}{x-2}=3\)
Đkxđ : x-2\(\ne\) 0\(\Leftrightarrow x\ne2\)
\(\Leftrightarrow\frac{2x+1}{x-2}-3=0\)
\(\Leftrightarrow\frac{2x+1-3\left(x-2\right)}{x-2}=0\)
\(\Leftrightarrow\frac{2x+1-3x+6}{x-2}=0\Leftrightarrow\frac{-x+7}{x-2}=0\)\(\Leftrightarrow-x+7=0\Leftrightarrow x=7\)